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10x^2-110x+280=0
a = 10; b = -110; c = +280;
Δ = b2-4ac
Δ = -1102-4·10·280
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-30}{2*10}=\frac{80}{20} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+30}{2*10}=\frac{140}{20} =7 $
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